x³- 4x²- x+1=(x-2)³
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quadratic equation. So we have to simplify the given equation before deciding whether it is quadratic equation or not.
SOLUTION:
Given Equation is x³ - 4x² - x + 1 = (x - 2)³
x³ - 4x² - x + 1 = x³ -3(x)²×2 +3x(2)² - (2)³
[ (a-b)³= a³ -3a²b + 3ab² - b³]
x³ - 4x² - x + 1 = x³ - 6x² + 12x - 8
x³ - x³ - 4x² +6x² - x - 12x + 1+8= 0
2x² -13x +9= 0
Which is of the form ax² + bx+c = 0
Hence, it is a quadratic equation.
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