Question

x3-4x2-x+1=(x-2)3 quadratic equation​

Answer 1

$\large\bold\red\star\:\underline{Solution:-}$

${x}^{3} - 4 {x}^{2} - x + 1 ={( x - 2) }^{3}. \\ \\ \cancel{x}^{3} - 4 {x}^{2} - x + 1 = \cancel{{x }^{3} } - {(2)}^{3} - 6x(x - 2). \\ \\ - 4 {x}^{2} - x + 1 = - 8 - 6 {x}^{2} + 12x. \\ \\ {2x}^{2} - 13x + 9 = 0.$

$Yes, \: \red{{x}^{3} -4 {x}^{2} -x+1={(x-2) }^{3} }have \: quadratic \: equation.$

Answer 2

Answer:

your answer is in the following image