Question

x³-4x²-x+1=(x+2)³ write the equation in the form of a quadratic equation and write x²,x and x0 their coefficients ​

Answer 1

Answer:

${x}^{3} - {4x}^{2} - x + 1 = {(x + 2)}^{3} \\ {x}^{3} - 4 {x}^{2} - x + 1 = {x}^{3} + 3 {x}^{2} \times (2) + 3x \times {(2)}^{2} + {2}^{3} \\ - {4x}^{2} - x + 1 = 6 {x}^{2} + 12x + 8 \\ {10x}^{2} + 13x + 7 = 0$

Coeff. of x² = 10

Coeff. of x = 13

Constant term = 7

Answer 2

Step-by-step explanation:

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