Question

X³ + 5x²- 14x =0 solve this question by hit and trial method​

Answer 1

Answer:

${x}^{3} + 5 {x}^{2} - 14x = 0$

by trial , let x= 2

substituting the values

=2*2*2 + 5*2*2 - 14*2

=8+20-28

=0

hence zero of the polynomial is -2

therefore first factor is x-2

perform long division by taking x-2 as divisor and the given polynomial as dividend

dividend = divisor * quotient + remainder

bcoz I m not able to represent the division here , I m writing the quotient directly

quotient is

${x}^{2} + 7$

therefore by factorisation

the given polynomial =

$( {x}^{2} + 7) (x - 2)$