Question

x³-6x²+11x-6 ÷(x-3) Divide and write a quotient and reminder​

Answer 1

Answer:

Let f(x)=x

3

−6x

2

+11x−6

and p(x)=x−2

Dividing f(x) by p(x) we get

Quotient q(x)=x

2

−4x+3 and Remainder r(x)=0

p(x)q(x)=(x−2)(x

2

−4x+3)

p(x)q(x)=x

3

−4x

2

+3x−2x

2

+8x−6

p(x)q(x)=x

3

−6x

2

+11x−6

⇒p(x)q(x)=f(x)

⇒p(x)q(x)+0=f(x)

⇒p(x)q(x)+r(x)=f(x)

Answer 2

Answer:

quotient :  x²-3x+2

remainder : 0

Step-by-step explanation:

x³-6x²+11x-6 ÷(x-3)

let x-3 = 0  => x = 3

using synthetic division method,

 3   I   1  -6  11  -6

      I   0  3  -9   6

      ______________

           1  -3  2 I  0

=> quotient :  x²-3x+2

    remainder : 0