Question

x³-6x²+11x-6/x-3 solve it please ​

Answer 1

Answer:

x3−6x2+11x−6

x3−6x2+11x−6=x3−5x2−x2+6x+5x−6

x3−6x2+11x−6=x3−5x2−x2+6x+5x−6=x3−5x2+6x−x2+5x−6

x3−6x2+11x−6=x3−5x2−x2+6x+5x−6=x3−5x2+6x−x2+5x−6=x(x2−5x+6)−1(x2−5x+6)

x3−6x2+11x−6=x3−5x2−x2+6x+5x−6=x3−5x2+6x−x2+5x−6=x(x2−5x+6)−1(x2−5x+6)=(x−1)(x2−5x+6)

x3−6x2+11x−6=x3−5x2−x2+6x+5x−6=x3−5x2+6x−x2+5x−6=x(x2−5x+6)−1(x2−5x+6)=(x−1)(x2−5x+6)=(x−1)(x2−2x−3x+6)

x3−6x2+11x−6=x3−5x2−x2+6x+5x−6=x3−5x2+6x−x2+5x−6=x(x2−5x+6)−1(x2−5x+6)=(x−1)(x2−5x+6)=(x−1)(x2−2x−3x+6)=(x−1)[x(x−2)−3(x−2)]

x3−6x2+11x−6=x3−5x2−x2+6x+5x−6=x3−5x2+6x−x2+5x−6=x(x2−5x+6)−1(x2−5x+6)=(x−1)(x2−5x+6)=(x−1)(x2−2x−3x+6)=(x−1)[x(x−2)−3(x−2)]=(x−1)(x−2)(x−3)

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