Question

X3-6x2+13x+16 is divided by x+2 using remainder theorm

Answer 1

Answer:

remainder is 6

Step-by-step explanation:

zero of X+2 = -2

substituting -2,

-2^3 - 6(-2^2) + 13(-2) +16

-8 +24 -26 +16

=6

Answer 2

answer :-

The remainder = 2

Step-by-step explanation:

Let p(x)=x³-6x²+13x+60, g(x)=x+2

/* Remainder Theorem :

If p(x) is any polynomial of degree greater than or equal to 1 and p(x) is divided by the linear polynomial (x-a) ,then the remainder is p(a). */

Here ,

p(x) is divided by (x+2) then the remainder is p(-2).

p(-2) = (-2)³-6(-2)²+13(-2)+60

= -8-24-26+60

= -58+60

= 2

sorry this for 60