Question

x3-6x2+2x-4 dividedb(3x-1)​

Answer 1

Answer:

$the \: answer \: is \: \frac{ - 107}{27}$

Step-by-step explanation:

$zero \: of \:(3 x - 1) \: is \: \frac{ 1}{3} \\\ p(x) = {x}^{3} - 6 {x}^{2} + 2x - 4 \\ =( { \frac{1}{3}) }^{3} - 6( { \frac{1}{3} )}^{2} + 2( \frac{1}{3} ) - 4 \\ = \frac{1}{27} - \frac{2}{3} + \frac{2}{3} - 4 \\ = \frac{1 - 108}{27} \\ p(x)= \frac{ - 107}{27}$

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