Question

x³ - 6x² + 3x + 10 factorise

Answer 1

I think some error in question

Answer 2

p(x)=x³-6x²+3x+10

p(2)=(2)³-6(2)²+3(2)+10=8-24+6+10=0

One factor is (x-2)

g(x)=(x-2)

[Refer the picture above for division]

Dividing p(x) by g(x) that is (x³-6x²+3x+10)÷(x-2) we get x²-4x-5

Splitting the middle term, we get,

x²-4x-5

x²-5x+1x-5

(x²-5x)(x-5)

x(x-5)+1(x-5)

(x+1)(x-5)

So the factors are:-

(x-2), (x+1), (x-5)

Thanks!!

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