Question

x³-6x²+3x+10 using factor theorem

Answer 1

f(x) = x³-6x²+3x+10
f(-1) = (−1)³−6(−1)²+(3)(−1)+10
(−1)³−6(−1)²+(3)(−1)+10
=0

So,(x+1) is the factor of f(x)
x³-6x²+3x+10/x+1
= x²-7x+10

(x+1) (x²-7x+10)
(x+1) (x−2)(x−5)