Question

x³+6x²+8x,x²-3x-10 Find the sum of the two numbers....​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$x( {x}^{2} + 6x + 8)$

$x( {x}^{2} + (4 + 2)x + 8)$

$x( {x}^{2} + 4x + 2x + 8)$

$x(x(x + 4) + 2(x + 4))$x[(x+2)(x+4)]

x = -2 or x = -4

-2[(-2+2)(-2+4)]

= 0

$x²-3x-10 \: will \: also \: be \: 0$

so the sum of twoo number =0+0 = 0

similarly