Question

x³-7x+14x+k=0 then find k which is in G.P
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Answer 1

Step-by-step explanation:

Let a, ß, y be the roots of x³ - 7x² + 14x + k = 0

a+B+y=7

αβ + βγ + γα = 14

αβγ = –k

Now as a, B, y is in G.P B² = ay

aßy-k

⇒ B³ = -k _ß =(-k) ³

Substituting this in equation we get

3 ((-k) ³ ) ³ − 7 ((-k) ³)³ + 14 ((-k) ¹) +k=0

k = - 8

Answer 2

Answer:

consturct triangles of the measures given below