x³-7x-6 factorise the polynomial
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Answered by
0
Answer:
Let p(x)=x3−7x+6
From figure, we have p(1)=0
Thus, (x−1) is a factor of p(x)
The other factor is x2+x−6
=(x+3)(x−2)
Therefore, x3−7x+6=(x−1)(x+3)(x−2)
Answered by
0
Answer:
Let p(x)=x
3
−7x+6
From figure, we have p(1)=0
Thus, (x−1) is a factor of p(x)
The other factor is x
2
+x−6
=(x+3)(x−2)
Therefore, x
3
−7x+6=(x−1)(x+3)(x−2)
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