Question

x³-7x²+19x-13=0
solve the following question​

Answer 1

Answer:

x³-7x²+19x-13=0

x(x²-7x+19)-13=0

x=13

x²-7x+19=0

b²-4ac

49-4(1))(19)

49-(4x19)

=-27

use formula method

x=7±root27/2

x=7±3root3/2

$x = \frac{7 + \sqrt{3} }{2 } \: \: and \: y = \frac{7 - \sqrt{3} }{2}$

hence proved it