Math, asked by samim1979ansari, 9 months ago

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x3-8 y3- 36xy – 216, का मान ज्ञात कीजिए, जब x = 2y + 6​

Answers

Answered by chaudharydipanshu
1

Answer:

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Step-by-step explanation:

x3-8y3 -216- 36.1.y = XS +(-2y)3+(-6)3-3.x(-2y)(-6)

= (x 6)(x2 + 4y2 + 36+ 2xy-I2y+ 6x)

= Ox(x2+ 4y2 + 36+2v-12y+ 6x)       [x =2y+ 6 ] =0  

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