Question

x3 + ax² + bx + c
roots.
1, 3, 3
show
c= -9​

Answer 1

${x}^{3} + a {x}^{2} + bx + c$

$( {x}^{3} + a {x}^{2} ) + bx + c$

$(a {x}^{5} + bx) + c$

$(ab {x}^{7} + c)$

$abc {x}^{7} \: \: is \: ur \: answer$