X³+kx²-10x-15 is divided by (x-3) remainder +7 find k
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Question :-
- Find k, if x³+ kx²- 10x - 15 is divided by (x-3), leaves the remainder 7.
Answer
Given :-
- when p(x) = x³+ kx²-10x-15 is divided by g(x) = x-3, it leaves the remainder 7.
To find :-
- Value if k.
Concept used :-
Remainder theorem:
- Let p(x) be any polynomial of degree greater than or equal to one and let a be any real number. If p(x) is divided by the linear polynomial x – a, then the remainder is p(a).
Solution:-
Since, p(x) = x³+ kx²- 10x - 15
and g(x) = x - 3
Remainder = 7
Now, p(x) is divided by x - 3,
therefore, by remainder theorem,
remainder is p(3)
According to statement,
Remainder = 7
⇛ p(3) = 7
⇛ (3)³+ k(3)²- 10 (3) - 15 = 0
⇛ 27 + 9k - 30 - 15 = 0
⇛ 9k - 18 = 0
⇛9k = 18
⇛ k = 2
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