Question

x3
${x}^{3} - 2x - 4$

Answer 1

${x}^{3} - 2x - 4 = \\ (x - 2)( {x}^{2} + 2x + 2) \\ so \: (x - 2) = 0 \: \: \: or \: \: \: \: {x}^{2} + 2x + 2 = 0 \\ but \: {x}^{2} + 2x + 2 = 0 \: is \: not \: possible \: \: \: so \: (x - 2) = 0 \\ so \: x = 2$
So x = 2