Question

x3-x+2,3x2+5x3-x+1,x2-2x+5,3x+x2+x3​

Answer 1

Solution:

Let A = x³-x+2,

B = 3x²+5x³-x+1,

C = x²-2x+5

D = 3x+x²+x³

Now ,

A+B+C+D

= x³-x+2+3x²+5x³-x+1+ x²-2x+5

+ 3x+x²+x³

= x³+5x³+x³+3x²+x²+x²-x-x-2x+3x+2+1+5

= (1+5+1)x³+(3+1+1)x²+(-1-1-2+3)x+8

= 7x³+5x²-x+8

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