Question

x³+x²=1 iteration method in numerical analysis​

Answer 1

Answer:

Hey ! mate here is my answer for your question

Step-by-step explanation:

you can write above x³ + x²=1

as,. x³+x² -1=0

let, d(x) =x³+x²-1

d(0)= -1(positive)

d(1)= 1(negative)

hence, the root value lie between 0 to 1

x3 + x 2 - 1 = 0

x2 (x + 1) = 1

x2 = 1/ (x + 1)

x = 1/ √(x + 1)

Let the initial approximation be

x0 = 0.5 x1 = pi(x0) = 1/√1+ 0.5 = 0.81649

I hope it will helps you.....!!! buddy

have a nice day :)

Answer 2

Answer:

x³+x²=-1 iteration methods in numerical analysis