x³+x²+1/ (x²+2)(x²+3) into partial fraction
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1
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ANSWER
(1+x)(1+x
2
)
7+x
=
1+x
A
+
1+x
2
Bx+C
⇒7+x=A(1+x
2
)+(Bx+C)(1+x)
⇒7+x=A(1+x
2
)+B(x+x
2
)+C(1+x)
On comparing coefficients
A+B=0,B+C=1,A+C=7⇒A=3,B=−3,C=4
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