Question

X3-x2-(2+√2)x+√2 where the value of x= -1

Answer 1

Hey dear!!

Here's your answer

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x^3-x^2-(2+√2)x+√2, here the value of 'x' is (-1)

${x}^{3} - {x}^{2} - (2 + \sqrt{2} )x + \sqrt{2} \\ = { (- 1)}^{3} - {( - 1)}^{2} - (2 + \sqrt{2} )( - 1)+ \sqrt{2} \\ = ( - 1) - ( + 1) - 2 \times ( - 1) - \sqrt{2} \times ( - 1) + {\sqrt{2} } \\ = - 1 - 1 + 2 + \sqrt{2} + \sqrt{2} \\ = 2 \sqrt{2}$
If any problem there then comment here.

Hope it helps!!

Answer 2

Step-by-step explanation:

x^3-x^2-(2+√2)x+√2, here the value of 'x' is (-1)

\begin{gathered} {x}^{3} - {x}^{2} - (2 + \sqrt{2} )x + \sqrt{2} \\ = { (- 1)}^{3} - {( - 1)}^{2} - (2 + \sqrt{2} )( - 1)+ \sqrt{2} \\ = ( - 1) - ( + 1) - 2 \times ( - 1) - \sqrt{2} \times ( - 1) + {\sqrt{2} } \\ = - 1 - 1 + 2 + \sqrt{2} + \sqrt{2} \\ = 2 \sqrt{2} \end{gathered}

x

3

−x

2

−(2+

2

)x+

2

=(−1)

3

−(−1)

2

−(2+

2

)(−1)+

2

=(−1)−(+1)−2×(−1)−

2

×(−1)+

2

=−1−1+2+

2

+

2

=2

2