x3-x2-(3-√3)x+√3 is divided by x+1
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Answer:
g(x)=x+1=0
x=-1
p(x)=x³-x²-(3-√3)x+√3
p(-1)=(-1)³-(-1)²-(3-√3)(-1)+√3
=-1-1+3-√3+√3
=1
therefore, remainder is 1
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