Question

x³-x²-(3-√3)x+√3
please tell me process​

Answer 1

⚠️INCORRECT QUESTION⚠️

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${\mathbb \color{red}{CORRECT \: QUESTION:-}}$

Determine x³-x²-(3-√3)x+√3 has ( X + 1 ) as a factor?

$\huge \bf {\mathtt \orange{SOLUTION}}$

Substitute ( -1 ) in the EQ [according to factor theorem],

P ( -1 ) = ( -1 )³ - ( -1 )² - ( 3 -V3 ) -1 + 13 = 0

p(-1)= (-1)³-(-1)²-(3-v3)-1+v3=0 =(-1) - 1 +3-13 +13=0 [-13&v3 cancels]

[-V3&v3 cancels] =-2+3

=(-1) not equal to O

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$\huge \bf \color{yellow}{(x+1) is \: not \: a \: factor \: of \: the} \: \red{eq}$