x3+x2-6x find factors
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x³+x²-6x
x(x²+x-6)
x(x²-3x+2x-6)
x{x(x-3) +2(x-3) }
x(x+2)(x-3)
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Answer:
x³ + x² - 6x = 0
x² + x - 6 = 0
x² + 3x - 2x -6 = 0
x(x+3)-2(x+3) = 0
(x+3)(x-2) = 0
So,x = -3 , 2
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