x³+x²+x+1 (x+1) as a facto
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x³ + x² – x – 1
=> (x³ + x²) - (x +1)
=> x² (x + 1) - ( x + 1)
=> (x² - 1)(x + 1)
=> (x² – 1²) (x + 1)
=> (x - 1)(x + 1)(x + 1) [using identity a²-b²=(a+b)(a-b)]
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