Math, asked by neal494, 11 months ago

x³-x²y +y³-xy² factorise


KshitijTripathi: you can reaarange to get, x^3+y^3-(xy^2+x^2y) then use x^3+y^3=(x+y)(x^2+y^2-xy) and x^2y-xy^2 as xy( x+y)
neal494: thanks

Answers

Answered by TRISHNADEVI
18
HERE IS YOUR ANSWER....


x {}^{3} - x {}^{2} y + y {}^{3} - xy {}^{2} \\ = x {}^{3} - x {}^{2} y - xy {}^{2} + y {}^{3} \\ = x {}^{2} (x - y) - y {}^{2} (x - y) \\ = (x - y)(x {}^{2} - y {}^{2} ) \\ = (x - y)(x - y)(x + y) \\ = (x - y) {}^{2} (x + y) \\ =( x {}^{2} + 2xy + y {}^{2} )(x + y)


HOPE IT IS HELPFUL FOR YOU
Answered by shabreensoqb788
4

Step-by-step explanation:

(x²- 2xy -y²) ( x+y) hope it helps

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