x³+y³+12xy=64 . Find x+y?
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we just take pair and we get 64
so, ( 2 +2)^3 = (4)^3
(4)^3= 64
now, x^3+y^3+12 xy =
let put the value of:
x=2
y=2
(2)^3+(2)^3 + 12 ×2×2 =64
8+8+12×4=64
16+ 48 =64
64=64
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