Question

x³ * y³
solve this question ​

Answer 1

SOLUTION: Let's start from the expansion of (x – y)³. Using binomial expansion, (x – y)³ = x³ – 3x²y + 3xy² – y³

By rearrangement,

(x – y)³ + 3x²y – 3xy² = x³ – y³

Put the other way round,

x³ – y³ = (x – y)³ + 3x²y – 3xy²

x³ – y³ = (x – y)³ + 3xy(x – y)

x³ – y³ = (x – y)(x – y)² + 3xy(x – y)

Now x – y is common, let's factorize

x³ – y³ = (x – y)[(x – y)² + 3xy]

x³ – y³ = (x – y)(x² – 2xy + y² + 3xy)

Collect like terms

x³ – y³ = (x – y)(x² + xy + y²)

Answer 2

Answer:

hope this will help you