Question

x³-y³=(x-y)(x²+xy+y²) verify the following​

Answer 1

Answer:

x3 - y3 = (x - y)(x2 + xy + y2)

(x - y)(x2 + xy + y2)

(x)(x2 + xy + y^2) + (-y)(x2 + xy + y2)

(x3 + x2y + xy2) + (-x2y - xy2 - y3)

x3 + x2y + xy2 - x2y - xy2 - y3

x3 - y3

Answer 2

Identity:-

•x³-y³=(x-y)(x²+xy+y²)

Proof:-

=>(x-y)³=(x³-y³)-3xy(x-y)

=>(x³-y³)=(x-y)³+3xy(x-y)

=>(x-y)[(x-y)²+3xy]

=>(x-y)(x²+xy+y²)

Thus,x³-y³=(x-y)(x²+xy+y²)