x³+y³+z³–3xyz= ? please answer
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Answer:
3xyz
Step-by-step explanation:
x^3 + y^3 + z^3 - 3xyz = (x + y + z) (x^2 + y^2 +z^2 - xy - yz - xz )
as acc to identity x + y + z = 0
then,
x^3 + y^3 + z^3 - 3xyz = 0
x^3 + y^3 + z ^3 = 3xyz
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