Question

x3+y3+z3-3xyz value x=-2,y=-1,z=3

Answer 1

$given \\ x = - 2 \\ y = - 1 \\ z = 3 \\ x + y + z = 0 \\ hence \\ {x}^{3} + {y}^{3} + {z}^{3} = 3xyz \\ \: hence \: {x}^{3} + {y}^{3} + {z}^{3} - 3xyz = 0$

Answer 2

first put the value and get -27...bcz apply the (x-y)hole power 3....