X³sec²y dy/dx + 3x²tany=cosx
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Answer:the answer of the question is
x^3×tany=sinx+c, [where c is arbitrary constant
Step-by-step explanation:We know, d/dx(x^3×tany) =3x^2×tany+x^3×sec^2y×dy/dx
So from the given equation we get,
d/dx(x^3×tany) =cosx
This implies, d(x^3×tany) =cosx dx
Integrating both sides, we get,
This implies, x^3×tany=sinx+c
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We can get easily as this direct exact equation
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