Question

x3y÷9-xy³÷16
factorise​

Answer 1

Answer:

${x}^{3} y \div 9 - x {y}^{3} \div 16 \\ \\ \\ = \frac{ {x}^{3} y}{9} - \frac{x {y}^{3} }{16} \\ \\ \\ = \frac{16 {x}^{3} y - 9x {y}^{3} }{144} \\ \\ \\ = \frac{xy(16 {x}^{2} - 9 {y}^{2}) }{144} \\ \\ \\ = \frac{xy( {4}^{2} {x}^{2} - {3}^{2} {y}^{2} )}{144} \\ \\ \\{ \large{ \pink{ = \frac{xy(4x - 3y)(4x + 3y)}{144} }}}$

Answer 2

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