Math, asked by bvsudhakar9570, 8 months ago

[x³y²·(-x²y)³·(-y²)³]:x³y⁵=

Answers

Answered by sfsgzdfgxggmailcom

0

x3y 3=X3 xy2

x2y 3=x2 x y3

and x4y 4 =x4 Xy4

*** HCF =x2 x y2=y2 y2

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