Math, asked by Jemraz17, 5 months ago

x³z⁵-5x³z²=x³z²(z³-__)

Answers

Answered by RvChaudharY50
2

Question :- x³z⁵-5x³z²=x³z²(z³- __)

Solution :-

Solving LHS part,

→ x³z⁵ - 5x³z²

breaking z⁵ by using a^m * a^n = a^(m + n)

  • 5 = 2 + 3

So,

→ x³ * z² * z³ - 5 * x³ * z²

as we can see 3 power of x and 2 power of z are common in both , So, taking common now,

x³ * z²(z³ - 5)

comparing with RHS part we get,

→ x³ * z²(z³ - 5) = x³z²(z³ - __)

→ x³ * z²(z³ - 5) = x³ * z²(z³ - __)

Therefore, 5 will come in the filling part.

Learn more :-

JEE mains Question :-

https://brainly.in/question/22246812

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