Question

x⁴-12x+11=0, how will you find the solution? what are the values of x?​

Answer 1

Step-by-step explanation:

$x {}^{4} - 12x + 11 = 0 \\ \\ = > x(x {}^{3} - 12 )= - 11 \\ \\ = > x = - 11 \\ \\ x {}^{3} - 12 = - 11 \\ \\ = > x {}^{3} = 1 \\ \\ = > x = \sqrt[3]{1} \\ \\ = > x = 1 \\ \\ \\ x = 1 \: and \: \: - 11$