Question

x⁴-16y⁴
pls solve this equation ​

Answer 1

$x^4 - 16y^4\\=> (x^2)^2 - (4y^2)^2\\Doing\ a^2 - b^2 formulae:-\\=> (x^2 + 4y^2) (x^2-4y^2)\\=> (x^2 + 4y^2) ((x)^2 - (2y)^2)\\=> (x^2 + 4y^2) (x+2y) (x-2y)$

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