Question

x⁴+22x³+121x
factorise by using identities or by regrouping​

Answer 1

Answer:

$(x)(x)(x + 11)(x + 11)$

Step-by-step explanation:

${x}^{4} + 22 {x}^{3} + 121x = {x}^{2} ( {x}^{2} + 22x + 121) \\ = {x}^{2} {(x + 11)}^{2} \\ = (x)(x)(x + 11)(x + 11)$

Answer 2

Step-by-step explanation:

Solution:

x^4 + 22x^3;+ 121x^2

[By splitting the middle term]

→ x^2 (x^2 + 22x + 121

→ (x + 11)^2

→ x^2 (x + 11)^2 Ans

Learn more :

48 + 22x - x

$48 + 22x - x ^{2}$

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