Question

x4+2x2y2+y4 factorize

Answer 1

(a+b)² = a²+b²+2ab
so (x+y)² =x²+y²+2xy
now compare it 
(x²)²+(y²)²+2x²y²
a=x² and b =y²
(a+b)²=(x²+y²)²=x^4+y^4+2x²y²
so (x²+y²)² is a factor of this equation 

Answer 2

Answer:

(x^2+y^2)^2

Step-by-step explanation:

(a+b)=a^2+b^2+2ab

(x+y)^2=x^2+y^2+2xy

(x^2)^2+(y^2)^2+2x^2y^2

a-x^2 and b=y^2

(a-b)^2=(x^2+y^2)^2=x^4+y^4+2x^2y^2

=x^4-2x^2y^2+y^4=(x^2+y^2)^2)