Question

x4 - 2x3 + x2 - 7x – 10, when X-1.​

Answer 1

Remainder = - 17

Quotient = x³ - x² - 7

Answer 2

$x ^{4} - 2x^{3} + x^{2} - 7x - 10 \\ when \: x - 1 \\ x - 1 = 0 \\ x = 0 + 1 \\ x = 1 \\ \\ = (1)^{4} -2(1)^{3} + (1)^{2} - 7(1) - 10 \\ = 1 - 2 + 1 - 7 - 10 \\ = 1 - 1 - 17 \\ = 1 - 18 \\ = - 17 \: (ans)$