( x⁴ +2xi) - (3x²+yi) = (3-5i) +(1+2yi) find the value of x and y , (x,y belongs to R)
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Answer:
(x² + 2xi) - (3x² + iy) = (3 − 5i) + (1+2iy)
(x¹ - 3x²)+i(2x - y) = 4+ (2y – 5)i
⇒ (x²-3x² - 4) +i(2x - y - 2y + 5) = 0
⇒x²-3x² -4 = 0 and 2x - 3y + 5 = 0
Now, x⁴-3x²-4 = 0⇒ (x² - 4)(x² + 1) =0
⇒x=2 or x = -2
(x = 2 ⇒ y = 3) and (x = -2 ⇒ y = 13)
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