Question

X4+7x3+7x-35x-60 has -3 and -4 as its zeroes.find the other zeroes.

Answer 1

Answer:

hi friend here is your answer...

${x}^{4} + 7 {x}^{3} + 7x - 35x - 60 \: has \: - 3 \: and \: - 4 \: as \: its \: zeroes... \\ solve... \\ {x}^{4} + 7 {x}^{3} + 7x - 35x - 60 \\ {x}^{4} + 7 {x}^{3} - 28x - 60 \\ given... \\ x = - 3 \: \: \: \: \: x = - 4 \\ (x + 3)(x + 4) \\ x(x + 4) + 3(x + 4) \\ {x}^{2} + 4x + 3x + 12 \\ {x}^{2} + 7x + 12 = q(x)$

hope its help you...