Question

(x4-81) \ (x3+3x2+9x+27)

Answer 1

Answer:

(x^4-81)(x^3+3x^2+9x+27)

={(x^2)^2-(9)^2}{x^2(x+3)+9(x+3)}

=(x^2+9)(x^2-9)(x+3)(x^2+9)

=(x^2+9)^2{(x)^2-(3)^2} (x+3)

=(x^2+9)^2(x+3)(x-3)(x+3)

=(x^2+9)^2(x+3)^2(x-3)