x4-(x-z)4 factorize than using identity a2-b2
Answers
Answered by
470
hi,
your answer in the picture below
mark as an brainliest thanks
your answer in the picture below
mark as an brainliest thanks
Attachments:
navyarajiv:
thanks a lott
most wlcm
:D
Answered by
165
Heyy...
Your answer is here.
x4-(x-z)4 is the given expression
let (x-z) = y
So, x^4 - y^4 = (x^2)^2 - (y^2)^2 = {(x^2) + (y^2)} {(x^2) - (y^2)} = {(x^2) + (y^2)} (x+y) (x-y)
Put the value of y into the found expression
= {(x^2) + (y^2)} (x+y) (x-y)
= {x^2+(x-z)^2} (x+x-z) (x-x+z)
= (x^2+x^2+z^2-2xz) (2x-z) (z)
= (2x^2+z^2-2xz) (2x-z)(z)
I this this may the correct answer.
Hope It Helps You...
Thankyou Buddy.
Your answer is here.
x4-(x-z)4 is the given expression
let (x-z) = y
So, x^4 - y^4 = (x^2)^2 - (y^2)^2 = {(x^2) + (y^2)} {(x^2) - (y^2)} = {(x^2) + (y^2)} (x+y) (x-y)
Put the value of y into the found expression
= {(x^2) + (y^2)} (x+y) (x-y)
= {x^2+(x-z)^2} (x+x-z) (x-x+z)
= (x^2+x^2+z^2-2xz) (2x-z) (z)
= (2x^2+z^2-2xz) (2x-z)(z)
I this this may the correct answer.
Hope It Helps You...
Thankyou Buddy.
Similar questions