Question

x4-(x-z)4 factorize than using identity a2-b2

Answer 1

hi,
your answer in the picture below
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Answer 2

Heyy...

Your answer is here.

x4-(x-z)4 is the given expression
let (x-z) = y
So, x^4 - y^4 = (x^2)^2 - (y^2)^2 = {(x^2) + (y^2)} {(x^2) - (y^2)} = {(x^2) + (y^2)} (x+y) (x-y)
Put the value of y into the found expression

= {(x^2) + (y^2)} (x+y) (x-y)
= {x^2+(x-z)^2} (x+x-z) (x-x+z)
= (x^2+x^2+z^2-2xz) (2x-z) (z)
= (2x^2+z^2-2xz) (2x-z)(z)

I this this may the correct answer.

Hope It Helps You...

Thankyou Buddy.