x⁴ +x² +1 factorise
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It is certainly possible over the real numbers, because in this setting the only nonlinear irreducible polynomials have degree two (and negative discriminant).
The simplest way is to complete a square:
x4+x2+1=x4+2x2+1−x2=(x2+1)2−x2=(x2+1−x)(x2+1+x)=(x2−x+1)(x2+x+1)
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