Question

X⁴-x²-12
please help me to solve this answer​

Answer 1

Answer:

=(x−2)(x+2)(x2+3)

Step-by-step explanation:

Use the difference of squares identity:

a2−b2=(a−b)(a+b)

with a=x and b=2 below.

Treat the quartic as a quadratic in x2, noting that 4⋅3=12 and 4−3=1, so:

x4−x2−12

=(x2)2−(x2)−12

=(x2−4)(x2+3)

=(x2−22)(x2+3)

=(x−2)(x+2)(x2+3)

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