x⁴+x²y²+y⁴
factorisze it
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To make the identity possible we take 2x^2y^2
x^4 + 2x^2y^2 - x^2y^2 + y^4
(x^2)^2 + (y^2)^2 + 2x^2y^2 - x^2y^2
(x^2+y^2)^2 - (xy)^2
(a+b)^2 - (c)^2 = (a+b-c)(a+b+c)
(x^2+y^2 +xy)(x^2+y^2 -xy)
x^4 + 2x^2y^2 - x^2y^2 + y^4
(x^2)^2 + (y^2)^2 + 2x^2y^2 - x^2y^2
(x^2+y^2)^2 - (xy)^2
(a+b)^2 - (c)^2 = (a+b-c)(a+b+c)
(x^2+y^2 +xy)(x^2+y^2 -xy)
anmita18:
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