Question

x4 + x3 - 9x2 - 3x + 9 find the roots if two roots are √3 and -√3

Answer 1

x4 + x3 - 9x2 - 3x + 9 = 0

zero/s = - root 3 and root 3

x - root3 = 0                 x + root3 = 0

(x - root3)^2                 (x + root3)^2

(x)^2 - 3

x^4 + x^3 - 9x^2 - 3x + 9 / x^2

= x^2 + x - 3

for other zeros:-

x^2 + x - 3 = 0

a = 1, b= 1, c= -3

D = b^2 - 4ac

D = (1)^2 - 4 x 1 x -3

D = 13

1st root = -b + rootD/2a

            = -1 + root13/2

2nd root = -b - rootD/2a

            = -1 - root13/2

roots = -1 + root13/2   &     -1 - root13/2

may it helps you

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