Question

X⁴-x³+x²+6= p(-1).
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Answer 1

Answer:

(-1)⁴-(1)³+(-1)²+6

1-1+1+6

ANSWER 7

Answer 2

Answer:

Q) p(x)=x^4-x^3+x^2+6

p(x)=0

p(-1)=(-1)^4-(-1)^3+(-1)^2+6

=1+1-1+6

=7

Remainder is 7.